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Optimizing Travel Time Using Derivatives

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Optimization of Travel Time Using Derivatives

Overview

A concise calculus explainer that shows how to minimize travel time by combining a beach run and a boat ride. The animation walks through problem setup, geometric modeling, derivation of the time function, differentiation, solving for the optimal running distance, and visual verification with a graph.


Phases

# Phase Name Duration Description
1 Intro ~12β€―s Fade‑in dark background, title "Optimization of Travel Time Using Derivatives" and subtitle "Technical Calculus Project – Highscope Indonesia Bali".
2 Problem Introduction ~20β€―s Show the narrative bullet points (starting point 10β€―mi west, station 3β€―mi offshore, speeds 9β€―mph on sand, 4β€―mph on water). Appear as simple icons (person, beach line, boat) with a brief pause for each bullet.
3 Geometry Visualization ~25β€―s Draw a horizontal beach line, mark the start point on the left, the offshore station above the line. Label the fixed distances (10β€―mi horizontal, 3β€―mi vertical). Introduce variable xx as the running distance; animate a movable point that slides xx units rightward, updating the remaining horizontal segment 10βˆ’x10-x.
4 Boat Distance Derivation ~30β€―s Highlight the right‑triangle formed by the boat path. Step‑by‑step reveal the Pythagorean relation y2=(10βˆ’x)2+32y^{2} = (10-x)^{2}+3^{2}, then simplify to y=(10βˆ’x)2+9y = \sqrt{(10-x)^{2}+9}. The triangle side lengths glow as each term appears.
5 Time Function Construction ~30β€―s Present the generic time formula time=distancespeed\text{time}=\frac{\text{distance}}{\text{speed}}. Show running time Trun=x9T_{run}=\frac{x}{9} and boat time Tboat=(10βˆ’x)2+94T_{boat}=\frac{\sqrt{(10-x)^{2}+9}}{4}. Combine them into the total‑time function T(x)=x9+(10βˆ’x)2+94T(x)=\frac{x}{9}+\frac{\sqrt{(10-x)^{2}+9}}{4}.
6 Derivative Calculation ~35β€―s Animate differentiation: first write Tβ€²(x)T'(x), then replace each term with its derivative, arriving at Tβ€²(x)=19βˆ’10βˆ’x4(10βˆ’x)2+9T'(x)=\frac{1}{9}-\frac{10-x}{4\sqrt{(10-x)^{2}+9}}. Highlight the subtraction sign to emphasize the minimization condition.
7 Solving the Critical Point ~40β€―s Set Tβ€²(x)=0T'(x)=0. Perform algebraic manipulations step‑by‑step (multiply, isolate the square root, square both sides, simplify) until the numeric solution xβ‰ˆ8.51x \approx 8.51 emerges. The value glows and is boxed.
8 Graph Visualization ~35β€―s Plot T(x)T(x) on a coordinate plane (x‑axis: running distance 0–10, y‑axis: time). Animate a point traveling along the curve from x=0x=0 to the minimum, pausing at xβ‰ˆ8.51x\approx8.51 and labeling "Minimum Travel Time" with a small vertical line to the curve.
9 Final Result ~15β€―s Fade in the statement "Optimal running distance: xβ‰ˆ8.51x \approx 8.51 miles" centered. Brief pause for emphasis.
10 Closing ~12β€―s Show final title "Calculus in Real Life" with subtext "Using derivatives to maximize efficiency" and credit block (Technical Calculus Project, Gung Radit & Naelli, Highscope Indonesia Bali). Fade out.

Layout

β”Œβ”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”
β”‚                       TOP AREA                         β”‚
β”œβ”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”¬β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€
β”‚                       β”‚                               β”‚
β”‚        LEFT AREA      β”‚          RIGHT AREA            β”‚
β”‚   (Diagram / Graph)   β”‚   (Equations / Labels)         β”‚
β”‚                       β”‚                               β”‚
β”œβ”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”΄β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€
β”‚                     BOTTOM AREA                        β”‚
β””β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”€β”˜

Area Descriptions

Area Content Notes
Top Title, subtitle, scene headings, closing title Fades in at the start of each major phase; centered, large font, glowing on dark background
Left Primary visual: geometric diagram (beach, triangle) or graph of T(x)T(x) Remains central focus; objects animate in place
Right Supporting equations, derivative steps, algebraic simplifications Appear line‑by‑line, aligned vertically, with a subtle glow to match the dark theme
Bottom Small captions, source credits, optional unit labels Small, non‑intrusive; appears only in the Closing phase

Notes

  • Dark background throughout; all text and formulas use a soft cyan/white glow for readability.
  • Transitions are smooth fades or slide‑ins; no abrupt cuts.
  • All numeric values are displayed with two‑decimal precision where appropriate (e.g., xβ‰ˆ8.51x \approx 8.51).
  • No spoken narration is encoded; the specification assumes a voice‑over will follow the visual cues.
  • The entire animation fits within a single Manim Scene class; phases are sequenced using self.wait() and self.play() calls (implementation omitted per instructions).
  • Keep total runtime around 3β€―minutesβ€―30β€―seconds (210β€―s) to respect the requested 3–4β€―minute length.

Created By

Naelli Naelli Timorisna FillouxNaelli Naelli Timorisna Filloux

Description

An animated calculus explainer shows how to minimize total travel time from a point on the beach to an offshore station by combining a run and a boat ride. The scene builds the geometric model, derives the distance and time formulas, differentiates the total‑time function, solves for the optimal running distance, and confirms the minimum with a graph, ending with the optimal distance result.

Created At

Mar 16, 2026, 08:22 AM

Duration

2:06

Tags

calculusoptimizationderivativesapplied-mathgeometry

Status

Completed
AI Model
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